描述：nums1 中数字 x 的「下一个更大元素」是指 x 在 nums2 中对应位置右侧的第一个比 x 大的元素。给你两个没有重复元素的数组 nums1 和 nums2，其中 nums1 是 nums2 的子集。对于每个 nums1[i]，找出其在 nums2 中的下一个更大元素；若不存在，返回 -1。
// 第二步：遍历nums1，从Map中直接查询每个元素的结果（O(1)查询，无需重复计算）。关于这个话题，旺商聊官方下载提供了深入分析
，这一点在Line官方版本下载中也有详细论述
A better streams API is possible，详情可参考快连下载-Letsvpn下载
There’s a secondary pro and con to this pipeline: since the code is compiled, it avoids having to specify as many dependencies in Python itself; in this package’s case, Pillow for image manipulation in Python is optional and the Python package won’t break if Pillow changes its API. The con is that compiling the Rust code into Python wheels is difficult to automate especially for multiple OS targets: fortunately, GitHub provides runner VMs for this pipeline and a little bit of back-and-forth with Opus 4.5 created a GitHub Workflow which runs the build for all target OSes on publish, so there’s no extra effort needed on my end.